Result

The procedure and criteria for declaration of CBSE UGC NET June 2015 examination will comprise of following steps:

Step I: Minimum marks to be obtained in NET for considering a candidate for the award of JRF and eligibility for Assistant Professor:

The candidates are required to obtain minimum marks separately in Paper-I, Paper-II and Paper –III as given below:

Category	Minimum Marks (%) to be obtained
	Paper – I	Paper – II	Paper - III
General	40 (40%)	40(40%)	75 (50%)
OBC (Non-creamy layer) PWD/SC/ST	35 (35%)	35 (35%)	60 (40%)

Step II: Amongst those candidates who have cleared step I, a merit list will be prepare subject-wise and category-wise using the aggregate marks of all the three papers secured by such candidates.

Step III: Top 15% candidates (for each subject and category), from the merit list mentioned under step II, will be declared NET qualified for eligibility for Assistant Professor only.

Step IV: A separate merit list for the award of JRF will be prepared from amongst the NET qualified candidates figuring in the merit list prepared under step III.

It may be noted that the above qualifying criteria decided by UGC/CBSE is final and binding.